dorabarbie518 dorabarbie518

03-03-2020
Physics

contestada

1) A force of 20 Newton acts on a bar having a cross sectional area of 0.8m^2 and length 10cm.calculate the stress developed in the bar

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Chelboy Chelboy

03-03-2020

Answer:25N/M^2

Explanation:

Force=20N Area=0.8M^2

Stress=force/area

Stress=20/0.8

Stress=25N/M^2

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