ccolburn1 ccolburn1
  • 03-12-2020
  • Mathematics
contestada

. An object is launched straight up into the air. It is launched from a height
of H feet off the ground. Its height H, in feet, at t seconds is given by the
equation H = -8t^2 + 40t + 18. Find all times t that the object is at a height
of 50 feet off the ground.

Respuesta :

nasir21606 nasir21606
  • 03-12-2020

Answer:

H=24

Step-by-step explanation:

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